Bennett Mechanical Comprehension Practice Test 2025 – The Complete All-in-One Guide to Exam Success!

Question: 1 / 400

A football player kicks a football at a velocity of 50.0 m/s at an angle of 37º. What is the time of flight of the ball?

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6.00 s

To determine the time of flight for a projectile, you can use the following formula derived from kinematic equations:

The time of flight \( T \) for a projectile launched at an angle can be calculated using the formula:

\[ T = \frac{2 \cdot V_0 \cdot \sin(\theta)}{g} \]

where \( V_0 \) is the initial velocity, \( \theta \) is the angle of launch, and \( g \) is the acceleration due to gravity (approximately 9.81 m/s²).

In this case, the initial velocity \( V_0 \) is 50.0 m/s and the launch angle \( \theta \) is 37º.

First, we find the vertical component of the velocity:

\[ V_{0y} = V_0 \cdot \sin(\theta) = 50.0 \cdot \sin(37º) \]

Using a calculator, \( \sin(37º) \approx 0.6018 \):

\[ V_{0y} \approx 50.0 \cdot 0.6018 \approx 30.09 \, m/s \]

Next, we

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