Bennett Mechanical Comprehension Practice Test 2025 – The Complete All-in-One Guide to Exam Success!

Question: 1 / 400

If wheel A has twice the radius of wheel B, how does the torque compare when the same force is applied?

Torque on wheel A is greater

When a force is applied to the edges of a wheel, the torque produced by that force depends on both the magnitude of the force and the radius of the wheel. Torque is calculated using the formula:

\[

\text{Torque} = \text{Force} \times \text{Radius}

\]

Given that wheel A has a radius that is twice as large as that of wheel B, if we apply the same force to both wheels, the torque for wheel A will be:

\[

\text{Torque}_A = \text{Force} \times (2 \times \text{Radius}_B)

\]

Meanwhile, the torque for wheel B will be:

\[

\text{Torque}_B = \text{Force} \times \text{Radius}_B

\]

When we compare the two, we see that the torque on wheel A is indeed larger, because it involves the larger radius. Specifically, since wheel A's radius is twice that of wheel B's, the torque on wheel A will be twice as much as the torque on wheel B for the same applied force. This situation demonstrates that increasing the radius of a wheel amplifies the torque generated, making wheel A more effective at rotating under the same

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Torque on wheel A is less

Torque on both wheels is equal

Torque on wheel B is greater

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